2r^2+3r=20

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Solution for 2r^2+3r=20 equation:


Simplifying
2r2 + 3r = 20

Reorder the terms:
3r + 2r2 = 20

Solving
3r + 2r2 = 20

Solving for variable 'r'.

Reorder the terms:
-20 + 3r + 2r2 = 20 + -20

Combine like terms: 20 + -20 = 0
-20 + 3r + 2r2 = 0

Factor a trinomial.
(-4 + -1r)(5 + -2r) = 0

Subproblem 1

Set the factor '(-4 + -1r)' equal to zero and attempt to solve: Simplifying -4 + -1r = 0 Solving -4 + -1r = 0 Move all terms containing r to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1r = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1r = 0 + 4 -1r = 0 + 4 Combine like terms: 0 + 4 = 4 -1r = 4 Divide each side by '-1'. r = -4 Simplifying r = -4

Subproblem 2

Set the factor '(5 + -2r)' equal to zero and attempt to solve: Simplifying 5 + -2r = 0 Solving 5 + -2r = 0 Move all terms containing r to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -2r = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -2r = 0 + -5 -2r = 0 + -5 Combine like terms: 0 + -5 = -5 -2r = -5 Divide each side by '-2'. r = 2.5 Simplifying r = 2.5

Solution

r = {-4, 2.5}

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